You are given an array of non-overlapping intervals intervals sorted by start. Insert newInterval in the correct position (merge if necessary).
intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8][[1,2],[3,10],[12,16]]end < new.startnew = [min(new[0],iv[0]), max(new[1],iv[1])]Intervals are sorted. Phase 1 adds those entirely before the new interval. Phase 2 merges all overlapping intervals in one pass. Phase 3 adds those entirely after.